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(2F)=3F^2+1
We move all terms to the left:
(2F)-(3F^2+1)=0
We get rid of parentheses
-3F^2+2F-1=0
a = -3; b = 2; c = -1;
Δ = b2-4ac
Δ = 22-4·(-3)·(-1)
Δ = -8
Delta is less than zero, so there is no solution for the equation
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